48=(x+10)(x)-(x-2)(x+8)

Solution for 48=(x+10)(x)-(x-2)(x+8) equation:

48=(x+10)(x)-(x-2)(x+8)

We move all terms to the left:

48-((x+10)(x)-(x-2)(x+8))=0

We multiply parentheses ..

-((x+10)x-(+x^2+8x-2x-16))+48=0


We calculate terms in parentheses: -((x+10)x-(+x^2+8x-2x-16)), so:

(x+10)x-(+x^2+8x-2x-16)

determiningTheFunctionDomain
-(+x^2+8x-2x-16)+(x+10)x

We multiply parentheses

-(+x^2+8x-2x-16)+x^2+10x

We get rid of parentheses

-x^2+x^2-8x+2x+10x+16

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)


We get rid of parentheses

-4x-16+48=0

We add all the numbers together, and all the variables

-4x+32=0

We move all terms containing x to the left, all other terms to the right

-4x=-32

x=-32/-4

x=+8