48=1/2(b)(3b-2)

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Solution for 48=1/2(b)(3b-2) equation: 



48=1/2(b)(3b-2)

We move all terms to the left:

48-(1/2(b)(3b-2))=0



Domain of the equation: 2b(3b-2))!=0

b∈R



We multiply all the terms by the denominator


-(1+48*2b(3b-2))=0



We calculate terms in parentheses: -(1+48*2b(3b-2)), so:

1+48*2b(3b-2)

determiningTheFunctionDomain
48*2b(3b-2)+1

Wy multiply elements

96b(3+1

Back to the equation:

-(96b(3+1)



We add all the numbers together, and all the variables

-(96b4=0

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