48=3(1+4v)+3(4+7v)

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Solution for 48=3(1+4v)+3(4+7v) equation: 



48=3(1+4v)+3(4+7v)

We move all terms to the left:

48-(3(1+4v)+3(4+7v))=0

We add all the numbers together, and all the variables

-(3(4v+1)+3(7v+4))+48=0



We calculate terms in parentheses: -(3(4v+1)+3(7v+4)), so:

3(4v+1)+3(7v+4)

We multiply parentheses

12v+21v+3+12

We add all the numbers together, and all the variables

33v+15

Back to the equation:

-(33v+15)



We get rid of parentheses

-33v-15+48=0

We add all the numbers together, and all the variables

-33v+33=0

We move all terms containing v to the left, all other terms to the right

-33v=-33

v=-33/-33

v=1

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