48=3b+3(23-2b)

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Solution for 48=3b+3(23-2b) equation: 



48=3b+3(23-2b)

We move all terms to the left:

48-(3b+3(23-2b))=0

We add all the numbers together, and all the variables

-(3b+3(-2b+23))+48=0



We calculate terms in parentheses: -(3b+3(-2b+23)), so:

3b+3(-2b+23)

We multiply parentheses

3b-6b+69

We add all the numbers together, and all the variables

-3b+69

Back to the equation:

-(-3b+69)



We get rid of parentheses

3b-69+48=0

We add all the numbers together, and all the variables

3b-21=0

We move all terms containing b to the left, all other terms to the right

3b=21

b=21/3

b=7

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