48w2=27

Solution for 48w2=27 equation:

48w^2=27

We move all terms to the left:

48w^2-(27)=0

a = 48; b = 0; c = -27;
Δ = b2-4ac
Δ = 02-4·48·(-27)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*48}=\frac{-72}{96}
=-3/4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*48}=\frac{72}{96}
=3/4
$