48x2+12x-90=0

Solution for 48x2+12x-90=0 equation:

48x^2+12x-90=0

a = 48; b = 12; c = -90;
Δ = b2-4ac
Δ = 122-4·48·(-90)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-132}{2*48}=\frac{-144}{96}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+132}{2*48}=\frac{120}{96}
=1+1/4
$