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48x^2+58x+15=0
a = 48; b = 58; c = +15;
Δ = b2-4ac
Δ = 582-4·48·15
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-22}{2*48}=\frac{-80}{96} =-5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+22}{2*48}=\frac{-36}{96} =-3/8 $
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