48z-12=28z=

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Solution for 48z-12=28z= equation: 



48z-12=28z=

We move all terms to the left:

48z-12-(28z)=0

We add all the numbers together, and all the variables

20z-12=0

We move all terms containing z to the left, all other terms to the right

20z=12

z=12/20

z=3/5

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