49(5x+2)=1/7(11-x)

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Solution for 49(5x+2)=1/7(11-x) equation: 



49(5x+2)=1/7(11-x)

We move all terms to the left:

49(5x+2)-(1/7(11-x))=0



Domain of the equation: 7(11-x))!=0

x∈R



We add all the numbers together, and all the variables

49(5x+2)-(1/7(-1x+11))=0

We multiply parentheses

245x-(1/7(-1x+11))+98=0

We multiply all the terms by the denominator


245x*7(-1x+11))-(1+98*7(-1x+11))=0

Wy multiply elements

1715x^2(-+686x(-=0

We use the square of the difference formula

1715x^2(-686x(-=0

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