49+16=c2

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Solution for 49+16=c2 equation:



49+16=c2
We move all terms to the left:
49+16-(c2)=0
We add all the numbers together, and all the variables
-1c^2+65=0
a = -1; b = 0; c = +65;
Δ = b2-4ac
Δ = 02-4·(-1)·65
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{65}}{2*-1}=\frac{0-2\sqrt{65}}{-2} =-\frac{2\sqrt{65}}{-2} =-\frac{\sqrt{65}}{-1} $
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{65}}{2*-1}=\frac{0+2\sqrt{65}}{-2} =\frac{2\sqrt{65}}{-2} =\frac{\sqrt{65}}{-1} $

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