49+c+15=3c+6

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Solution for 49+c+15=3c+6 equation:



49+c+15=3c+6
We move all terms to the left:
49+c+15-(3c+6)=0
We add all the numbers together, and all the variables
c-(3c+6)+64=0
We get rid of parentheses
c-3c-6+64=0
We add all the numbers together, and all the variables
-2c+58=0
We move all terms containing c to the left, all other terms to the right
-2c=-58
c=-58/-2
c=+29

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