49+x*x=25+(10-x)*(10-x)

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Solution for 49+x*x=25+(10-x)*(10-x) equation: 



49+x*x=25+(10-x)(10-x)

We move all terms to the left:

49+x*x-(25+(10-x)(10-x))=0

We add all the numbers together, and all the variables

x*x-(25+(-1x+10)(-1x+10))+49=0

Wy multiply elements

x^2-(25+(-1x+10)(-1x+10))+49=0

We multiply parentheses ..

x^2-(25+(+x^2-10x-10x+100))+49=0



We calculate terms in parentheses: -(25+(+x^2-10x-10x+100)), so:

25+(+x^2-10x-10x+100)

determiningTheFunctionDomain
(+x^2-10x-10x+100)+25

We get rid of parentheses

x^2-10x-10x+100+25

We add all the numbers together, and all the variables

x^2-20x+125

Back to the equation:

-(x^2-20x+125)



We get rid of parentheses

x^2-x^2+20x-125+49=0

We add all the numbers together, and all the variables

20x-76=0

We move all terms containing x to the left, all other terms to the right

20x=76

x=76/20

x=3+4/5

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