493=(241x2)+

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Solution for 493=(241x2)+ equation: 



493=(241x^2)+

We move all terms to the left:

493-((241x^2)+)=0

We get rid of parentheses

-241x^2+493-=0

We add all the numbers together, and all the variables

-241x^2=0

a = -241; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-241)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-482}=0$

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