49=(2r+3)/(r+3)2

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Solution for 49=(2r+3)/(r+3)2 equation: 



49=(2r+3)/(r+3)2

We move all terms to the left:

49-((2r+3)/(r+3)2)=0



Domain of the equation: (r+3)2)!=0

r∈R



We multiply all the terms by the denominator


-((2r+3)+49*(r+3)2)=0



We calculate terms in parentheses: -((2r+3)+49*(r+3)2), so:

(2r+3)+49*(r+3)2

We multiply parentheses

(2r+3)+98r+294

We get rid of parentheses

2r+98r+3+294

We add all the numbers together, and all the variables

100r+297

Back to the equation:

-(100r+297)



We get rid of parentheses

-100r-297=0

We move all terms containing r to the left, all other terms to the right

-100r=297

r=297/-100

r=-2+97/100

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