49=(r+3)+(2r+3)2

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Solution for 49=(r+3)+(2r+3)2 equation: 



49=(r+3)+(2r+3)2

We move all terms to the left:

49-((r+3)+(2r+3)2)=0



We calculate terms in parentheses: -((r+3)+(2r+3)2), so:

(r+3)+(2r+3)2

We multiply parentheses

(r+3)+4r+6

We get rid of parentheses

r+4r+3+6

We add all the numbers together, and all the variables

5r+9

Back to the equation:

-(5r+9)



We get rid of parentheses

-5r-9+49=0

We add all the numbers together, and all the variables

-5r+40=0

We move all terms containing r to the left, all other terms to the right

-5r=-40

r=-40/-5

r=+8

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