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49=1(3/10)b
We move all terms to the left:
49-(1(3/10)b)=0
Domain of the equation: 10)b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
-(1(+3/10)b)+49=0
We multiply all the terms by the denominator
-(1(+3+49*10)b)=0
We calculate terms in parentheses: -(1(+3+49*10)b), so:b=0/-1493
1(+3+49*10)b
We add all the numbers together, and all the variables
1493b
Back to the equation:
-(1493b)
b=0
Równanie nie ma rozwiązania
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