49=3(-8b-5)+8(3b+8)

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Solution for 49=3(-8b-5)+8(3b+8) equation: 



49=3(-8b-5)+8(3b+8)

We move all terms to the left:

49-(3(-8b-5)+8(3b+8))=0



We calculate terms in parentheses: -(3(-8b-5)+8(3b+8)), so:

3(-8b-5)+8(3b+8)

We multiply parentheses

-24b+24b-15+64

We add all the numbers together, and all the variables

49

Back to the equation:

-(49)



We add all the numbers together, and all the variables

=0

b=0/1

b=0

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