49=5(3c+3)-3c

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Solution for 49=5(3c+3)-3c equation:



49=5(3c+3)-3c
We move all terms to the left:
49-(5(3c+3)-3c)=0
We calculate terms in parentheses: -(5(3c+3)-3c), so:
5(3c+3)-3c
We add all the numbers together, and all the variables
-3c+5(3c+3)
We multiply parentheses
-3c+15c+15
We add all the numbers together, and all the variables
12c+15
Back to the equation:
-(12c+15)
We get rid of parentheses
-12c-15+49=0
We add all the numbers together, and all the variables
-12c+34=0
We move all terms containing c to the left, all other terms to the right
-12c=-34
c=-34/-12
c=2+5/6

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