49=7(x-1)(x-1)

Solution for 49=7(x-1)(x-1) equation:

49=7(x-1)(x-1)

We move all terms to the left:

49-(7(x-1)(x-1))=0

We multiply parentheses ..

-(7(+x^2-1x-1x+1))+49=0


We calculate terms in parentheses: -(7(+x^2-1x-1x+1)), so:

7(+x^2-1x-1x+1)

We multiply parentheses

7x^2-7x-7x+7

We add all the numbers together, and all the variables

7x^2-14x+7

Back to the equation:

-(7x^2-14x+7)


We get rid of parentheses

-7x^2+14x-7+49=0

We add all the numbers together, and all the variables

-7x^2+14x+42=0

a = -7; b = 14; c = +42;
Δ = b2-4ac
Δ = 142-4·(-7)·42
Δ = 1372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1372}=\sqrt{196*7}=\sqrt{196}*\sqrt{7}=14\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14\sqrt{7}}{2*-7}=\frac{-14-14\sqrt{7}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14\sqrt{7}}{2*-7}=\frac{-14+14\sqrt{7}}{-14}
$