49p2+371p-163=5

Solution for 49p2+371p-163=5 equation:

49p^2+371p-163=5

We move all terms to the left:

49p^2+371p-163-(5)=0

We add all the numbers together, and all the variables

49p^2+371p-168=0

a = 49; b = 371; c = -168;
Δ = b2-4ac
Δ = 3712-4·49·(-168)
Δ = 170569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{170569}=413$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(371)-413}{2*49}=\frac{-784}{98}
=-8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(371)+413}{2*49}=\frac{42}{98}
=3/7
$