49p2+371p-163=5

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Solution for 49p2+371p-163=5 equation:



49p^2+371p-163=5
We move all terms to the left:
49p^2+371p-163-(5)=0
We add all the numbers together, and all the variables
49p^2+371p-168=0
a = 49; b = 371; c = -168;
Δ = b2-4ac
Δ = 3712-4·49·(-168)
Δ = 170569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{170569}=413$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(371)-413}{2*49}=\frac{-784}{98} =-8 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(371)+413}{2*49}=\frac{42}{98} =3/7 $

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