49r2+28r+4=0

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Solution for 49r2+28r+4=0 equation: 



49r^2+28r+4=0

a = 49; b = 28; c = +4;
Δ = b2-4ac
Δ = 282-4·49·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{-28}{98}=-2/7$

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