49t(2)-14t+1=0

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Solution for 49t(2)-14t+1=0 equation: 



49t(2)-14t+1=0

We add all the numbers together, and all the variables

49t^2-14t+1=0

a = 49; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·49·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{14}{98}=1/7$

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