49x+22x(x-444)=14763

Solution for 49x+22x(x-444)=14763 equation:

49x+22x(x-444)=14763

We move all terms to the left:

49x+22x(x-444)-(14763)=0

We multiply parentheses

22x^2+49x-9768x-14763=0

We add all the numbers together, and all the variables

22x^2-9719x-14763=0

a = 22; b = -9719; c = -14763;
Δ = b2-4ac
Δ = -97192-4·22·(-14763)
Δ = 95758105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9719)-\sqrt{95758105}}{2*22}=\frac{9719-\sqrt{95758105}}{44}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9719)+\sqrt{95758105}}{2*22}=\frac{9719+\sqrt{95758105}}{44}
$