49x2+182x+169=0

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Solution for 49x2+182x+169=0 equation: 



49x^2+182x+169=0

a = 49; b = 182; c = +169;
Δ = b2-4ac
Δ = 1822-4·49·169
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-182}{98}=-1+6/7$

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