49x2+4=28x

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Solution for 49x2+4=28x equation: 



49x^2+4=28x

We move all terms to the left:

49x^2+4-(28x)=0

a = 49; b = -28; c = +4;
Δ = b2-4ac
Δ = -282-4·49·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{28}{98}=2/7$

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