49x2-122x+64=0

Solution for 49x2-122x+64=0 equation:

49x^2-122x+64=0

a = 49; b = -122; c = +64;
Δ = b2-4ac
Δ = -1222-4·49·64
Δ = 2340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2340}=\sqrt{36*65}=\sqrt{36}*\sqrt{65}=6\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-122)-6\sqrt{65}}{2*49}=\frac{122-6\sqrt{65}}{98}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-122)+6\sqrt{65}}{2*49}=\frac{122+6\sqrt{65}}{98}
$