49x2-196=0

Solution for 49x2-196=0 equation:

49x^2-196=0

a = 49; b = 0; c = -196;
Δ = b2-4ac
Δ = 02-4·49·(-196)
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-196}{2*49}=\frac{-196}{98}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+196}{2*49}=\frac{196}{98}
=2
$