49x2-70x+25=0

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Solution for 49x2-70x+25=0 equation: 



49x^2-70x+25=0

a = 49; b = -70; c = +25;
Δ = b2-4ac
Δ = -702-4·49·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{70}{98}=5/7$

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