49x2=1

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Solution for 49x2=1 equation:



49x^2=1
We move all terms to the left:
49x^2-(1)=0
a = 49; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·49·(-1)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14}{2*49}=\frac{-14}{98} =-1/7 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14}{2*49}=\frac{14}{98} =1/7 $

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