49y=16(3y+10)

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Solution for 49y=16(3y+10) equation: 



49y=16(3y+10)

We move all terms to the left:

49y-(16(3y+10))=0



We calculate terms in parentheses: -(16(3y+10)), so:

16(3y+10)

We multiply parentheses

48y+160

Back to the equation:

-(48y+160)



We get rid of parentheses

49y-48y-160=0

We add all the numbers together, and all the variables

y-160=0

We move all terms containing y to the left, all other terms to the right

y=160

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