4=(1/3)(4x+9)

Solution for 4=(1/3)(4x+9) equation:

4=(1/3)(4x+9)

We move all terms to the left:

4-((1/3)(4x+9))=0


Domain of the equation: 3)(4x+9))!=0

x∈R


We add all the numbers together, and all the variables

-((+1/3)(4x+9))+4=0

We multiply parentheses ..

-((+4x^2+1/3*9))+4=0

We multiply all the terms by the denominator


-((+4x^2+1+4*3*9))=0


We calculate terms in parentheses: -((+4x^2+1+4*3*9)), so:

(+4x^2+1+4*3*9)

We get rid of parentheses

4x^2+1+4*3*9

We add all the numbers together, and all the variables

4x^2+109

Back to the equation:

-(4x^2+109)


We get rid of parentheses

-4x^2-109=0

a = -4; b = 0; c = -109;
Δ = b2-4ac
Δ = 02-4·(-4)·(-109)
Δ = -1744
Delta is less than zero, so there is no solution for the equation