4=(12-z)

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Solution for 4=(12-z) equation: 



4=(12-z)

We move all terms to the left:

4-((12-z))=0

We add all the numbers together, and all the variables

-((-1z+12))+4=0



We calculate terms in parentheses: -((-1z+12)), so:

(-1z+12)

We get rid of parentheses

-1z+12

Back to the equation:

-(-1z+12)



We get rid of parentheses

1z-12+4=0

We add all the numbers together, and all the variables

z-8=0

We move all terms containing z to the left, all other terms to the right

z=8

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