4=(12/5)+x

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Solution for 4=(12/5)+x equation: 



4=(12/5)+x

We move all terms to the left:

4-((12/5)+x)=0



Domain of the equation: 5)+x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+12/5)+x)+4=0

We multiply all the terms by the denominator


-((+12+4*5)+x)=0



We calculate terms in parentheses: -((+12+4*5)+x), so:

(+12+4*5)+x

determiningTheFunctionDomain
x+(+12+4*5)

We add all the numbers together, and all the variables

x+32

Back to the equation:

-(x+32)



We get rid of parentheses

-x-32=0

We add all the numbers together, and all the variables

-1x-32=0

We move all terms containing x to the left, all other terms to the right

-x=32

x=32/-1

x=-32

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