4=(3/7)(3x+14)

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Solution for 4=(3/7)(3x+14) equation:



4=(3/7)(3x+14)
We move all terms to the left:
4-((3/7)(3x+14))=0
Domain of the equation: 7)(3x+14))!=0
x∈R
We add all the numbers together, and all the variables
-((+3/7)(3x+14))+4=0
We multiply parentheses ..
-((+9x^2+3/7*14))+4=0
We multiply all the terms by the denominator
-((+9x^2+3+4*7*14))=0
We calculate terms in parentheses: -((+9x^2+3+4*7*14)), so:
(+9x^2+3+4*7*14)
We get rid of parentheses
9x^2+3+4*7*14
We add all the numbers together, and all the variables
9x^2+395
Back to the equation:
-(9x^2+395)
We get rid of parentheses
-9x^2-395=0
a = -9; b = 0; c = -395;
Δ = b2-4ac
Δ = 02-4·(-9)·(-395)
Δ = -14220
Delta is less than zero, so there is no solution for the equation

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