4=(3/7)(3x+14)

Solution for 4=(3/7)(3x+14) equation:

4=(3/7)(3x+14)

We move all terms to the left:

4-((3/7)(3x+14))=0


Domain of the equation: 7)(3x+14))!=0

x∈R


We add all the numbers together, and all the variables

-((+3/7)(3x+14))+4=0

We multiply parentheses ..

-((+9x^2+3/7*14))+4=0

We multiply all the terms by the denominator


-((+9x^2+3+4*7*14))=0


We calculate terms in parentheses: -((+9x^2+3+4*7*14)), so:

(+9x^2+3+4*7*14)

We get rid of parentheses

9x^2+3+4*7*14

We add all the numbers together, and all the variables

9x^2+395

Back to the equation:

-(9x^2+395)


We get rid of parentheses

-9x^2-395=0

a = -9; b = 0; c = -395;
Δ = b2-4ac
Δ = 02-4·(-9)·(-395)
Δ = -14220
Delta is less than zero, so there is no solution for the equation