4=(3y+13)

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Solution for 4=(3y+13) equation: 



4=(3y+13)

We move all terms to the left:

4-((3y+13))=0



We calculate terms in parentheses: -((3y+13)), so:

(3y+13)

We get rid of parentheses

3y+13

Back to the equation:

-(3y+13)



We get rid of parentheses

-3y-13+4=0

We add all the numbers together, and all the variables

-3y-9=0

We move all terms containing y to the left, all other terms to the right

-3y=9

y=9/-3

y=-3

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