4=(7c+3)+

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Solution for 4=(7c+3)+ equation: 



4=(7c+3)+

We move all terms to the left:

4-((7c+3)+)=0



We calculate terms in parentheses: -((7c+3)+), so:

(7c+3)+

We add all the numbers together, and all the variables

(7c+3)

We get rid of parentheses

7c+3

Back to the equation:

-(7c+3)



We get rid of parentheses

-7c-3+4=0

We add all the numbers together, and all the variables

-7c+1=0

We move all terms containing c to the left, all other terms to the right

-7c=-1

c=-1/-7

c=1/7

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