4=(8y+3)-1

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Solution for 4=(8y+3)-1 equation: 



4=(8y+3)-1

We move all terms to the left:

4-((8y+3)-1)=0



We calculate terms in parentheses: -((8y+3)-1), so:

(8y+3)-1

We get rid of parentheses

8y+3-1

We add all the numbers together, and all the variables

8y+2

Back to the equation:

-(8y+2)



We get rid of parentheses

-8y-2+4=0

We add all the numbers together, and all the variables

-8y+2=0

We move all terms containing y to the left, all other terms to the right

-8y=-2

y=-2/-8

y=1/4

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