4=-3(24-b)+2(b-2)

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Solution for 4=-3(24-b)+2(b-2) equation: 



4=-3(24-b)+2(b-2)

We move all terms to the left:

4-(-3(24-b)+2(b-2))=0

We add all the numbers together, and all the variables

-(-3(-1b+24)+2(b-2))+4=0



We calculate terms in parentheses: -(-3(-1b+24)+2(b-2)), so:

-3(-1b+24)+2(b-2)

We multiply parentheses

3b+2b-72-4

We add all the numbers together, and all the variables

5b-76

Back to the equation:

-(5b-76)



We get rid of parentheses

-5b+76+4=0

We add all the numbers together, and all the variables

-5b+80=0

We move all terms containing b to the left, all other terms to the right

-5b=-80

b=-80/-5

b=+16

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