4=-3/2(-2)+b

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Solution for 4=-3/2(-2)+b equation: 



4=-3/2(-2)+b

We move all terms to the left:

4-(-3/2(-2)+b)=0



Domain of the equation: 2(-2)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-3+4*2(-2)+b)=0



We calculate terms in parentheses: -(-3+4*2(-2)+b), so:

-3+4*2(-2)+b

determiningTheFunctionDomain
b-3+4*2(-2)

We add all the numbers together, and all the variables

b-19

Back to the equation:

-(b-19)



We get rid of parentheses

-b+19=0

We add all the numbers together, and all the variables

-1b+19=0

We move all terms containing b to the left, all other terms to the right

-b=-19

b=-19/-1

b=+19

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