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4=-5x+8/2x-6
We move all terms to the left:
4-(-5x+8/2x-6)=0
Domain of the equation: 2x-6)!=0We get rid of parentheses
x∈R
5x-8/2x+6+4=0
We multiply all the terms by the denominator
5x*2x+6*2x+4*2x-8=0
Wy multiply elements
10x^2+12x+8x-8=0
We add all the numbers together, and all the variables
10x^2+20x-8=0
a = 10; b = 20; c = -8;
Δ = b2-4ac
Δ = 202-4·10·(-8)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12\sqrt{5}}{2*10}=\frac{-20-12\sqrt{5}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12\sqrt{5}}{2*10}=\frac{-20+12\sqrt{5}}{20} $
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