4=2(2b+2)-68

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Solution for 4=2(2b+2)-68 equation: 



4=2(2b+2)-68

We move all terms to the left:

4-(2(2b+2)-68)=0



We calculate terms in parentheses: -(2(2b+2)-68), so:

2(2b+2)-68

We multiply parentheses

4b+4-68

We add all the numbers together, and all the variables

4b-64

Back to the equation:

-(4b-64)



We get rid of parentheses

-4b+64+4=0

We add all the numbers together, and all the variables

-4b+68=0

We move all terms containing b to the left, all other terms to the right

-4b=-68

b=-68/-4

b=+17

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