4=2(7r+5)+6

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Solution for 4=2(7r+5)+6 equation: 



4=2(7r+5)+6

We move all terms to the left:

4-(2(7r+5)+6)=0



We calculate terms in parentheses: -(2(7r+5)+6), so:

2(7r+5)+6

We multiply parentheses

14r+10+6

We add all the numbers together, and all the variables

14r+16

Back to the equation:

-(14r+16)



We get rid of parentheses

-14r-16+4=0

We add all the numbers together, and all the variables

-14r-12=0

We move all terms containing r to the left, all other terms to the right

-14r=12

r=12/-14

r=-6/7

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