4=2(j+1)-4

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Solution for 4=2(j+1)-4 equation: 



4=2(j+1)-4

We move all terms to the left:

4-(2(j+1)-4)=0



We calculate terms in parentheses: -(2(j+1)-4), so:

2(j+1)-4

We multiply parentheses

2j+2-4

We add all the numbers together, and all the variables

2j-2

Back to the equation:

-(2j-2)



We get rid of parentheses

-2j+2+4=0

We add all the numbers together, and all the variables

-2j+6=0

We move all terms containing j to the left, all other terms to the right

-2j=-6

j=-6/-2

j=+3

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