4=2+(2/5)t

Solution for 4=2+(2/5)t equation:

4=2+(2/5)t

We move all terms to the left:

4-(2+(2/5)t)=0


Domain of the equation: 5)t)!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

-(2+(+2/5)t)+4=0

We multiply all the terms by the denominator


-(2+(+2+4*5)t)=0


We calculate terms in parentheses: -(2+(+2+4*5)t), so:

2+(+2+4*5)t

determiningTheFunctionDomain
(+2+4*5)t+2

We add all the numbers together, and all the variables

22t+2

Back to the equation:

-(22t+2)


We get rid of parentheses

-22t-2=0

We move all terms containing t to the left, all other terms to the right

-22t=2

t=2/-22

t=-1/11