4=2/3(5)+b

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Solution for 4=2/3(5)+b equation: 



4=2/3(5)+b

We move all terms to the left:

4-(2/3(5)+b)=0



Domain of the equation: 35+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-35

b!=-35/1

b!=-35

b∈R



We add all the numbers together, and all the variables

-(+b+2/35)+4=0

We get rid of parentheses

-b+4-2/35=0

We multiply all the terms by the denominator


-b*35-2+4*35=0

We add all the numbers together, and all the variables

-b*35+138=0

Wy multiply elements

-35b+138=0

We move all terms containing b to the left, all other terms to the right

-35b=-138

b=-138/-35

b=3+33/35

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