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4=2/3(x+5)
We move all terms to the left:
4-(2/3(x+5))=0
Domain of the equation: 3(x+5))!=0We multiply all the terms by the denominator
x∈R
-(2+4*3(x+5))=0
We calculate terms in parentheses: -(2+4*3(x+5)), so:
2+4*3(x+5)
determiningTheFunctionDomain 4*3(x+5)+2
Wy multiply elements
12x(x+2
Back to the equation:
-(12x(x+2)
We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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We calculate terms in parentheses: -(12x(x+2), so:
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