4=2c+2(-2c-5)

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Solution for 4=2c+2(-2c-5) equation: 



4=2c+2(-2c-5)

We move all terms to the left:

4-(2c+2(-2c-5))=0



We calculate terms in parentheses: -(2c+2(-2c-5)), so:

2c+2(-2c-5)

We multiply parentheses

2c-4c-10

We add all the numbers together, and all the variables

-2c-10

Back to the equation:

-(-2c-10)



We get rid of parentheses

2c+10+4=0

We add all the numbers together, and all the variables

2c+14=0

We move all terms containing c to the left, all other terms to the right

2c=-14

c=-14/2

c=-7

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