4=3(c+1)-5

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Solution for 4=3(c+1)-5 equation: 



4=3(c+1)-5

We move all terms to the left:

4-(3(c+1)-5)=0



We calculate terms in parentheses: -(3(c+1)-5), so:

3(c+1)-5

We multiply parentheses

3c+3-5

We add all the numbers together, and all the variables

3c-2

Back to the equation:

-(3c-2)



We get rid of parentheses

-3c+2+4=0

We add all the numbers together, and all the variables

-3c+6=0

We move all terms containing c to the left, all other terms to the right

-3c=-6

c=-6/-3

c=+2

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