4=3(z-5)-2

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Solution for 4=3(z-5)-2 equation: 



4=3(z-5)-2

We move all terms to the left:

4-(3(z-5)-2)=0



We calculate terms in parentheses: -(3(z-5)-2), so:

3(z-5)-2

We multiply parentheses

3z-15-2

We add all the numbers together, and all the variables

3z-17

Back to the equation:

-(3z-17)



We get rid of parentheses

-3z+17+4=0

We add all the numbers together, and all the variables

-3z+21=0

We move all terms containing z to the left, all other terms to the right

-3z=-21

z=-21/-3

z=+7

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