4=4(c+12)

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Solution for 4=4(c+12) equation: 



4=4(c+12)

We move all terms to the left:

4-(4(c+12))=0



We calculate terms in parentheses: -(4(c+12)), so:

4(c+12)

We multiply parentheses

4c+48

Back to the equation:

-(4c+48)



We get rid of parentheses

-4c-48+4=0

We add all the numbers together, and all the variables

-4c-44=0

We move all terms containing c to the left, all other terms to the right

-4c=44

c=44/-4

c=-11

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